5m^2-4m+4=16

Solution for 5m^2-4m+4=16 equation:

5m^2-4m+4=16

We move all terms to the left:

5m^2-4m+4-(16)=0

We add all the numbers together, and all the variables

5m^2-4m-12=0

a = 5; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·5·(-12)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*5}=\frac{-12}{10}
=-1+1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*5}=\frac{20}{10}
=2
$